Using the law of cosines and sines, the measure of angle B is: 38.4°.
<h3>What is the Law of Cosines and Sines?</h3>
Law of cosines is: c = √[a² + b² ﹣ 2ab(cos C)]
Law of sines is: sin A/a = sin B/b = sin C/c
Use the law of cosines to find c:
c = √[12² + 18² ﹣ 2(12)(18)(cos 117)]
c ≈ 25.8
Use the law of sines to find angle B:
sin B/b = sin C/c
sin B/18 = sin 117/25.8
sin B = (sin 117 × 18)/25.8
sin B = 0.6216
B = sin^(-1)(0.6216)
B = 38.4°
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Answer:
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Step-by-step explanation:
Answer:
C - 10
Step-by-step explanation:
n is the number of the term
an = -2n+8
a9 = -2*9 +8
a9 = -18+8
a9 = -10
The 9th term is -10
Your answer is:
2n-4
Step by step:
(n+8)+(n-12)
Rewrite and remove the parentheses
n+8+n-12
Calculate
Therefore your solution is:
2n-4
There seems to be a problem with your question - AEC does not create a triangle while ADE does.
As for finding x
Draw an imaginary line from C to D. 3^2+4^2=5^2, so take the square root to find CD=5. Now we know that CA is also 5. To find x, x^2+3^2=5^2, or x^2+9=25. Subtract 9 from both sides to get 16, and take the square root of both sides to get x=4.
