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pav-90 [236]
3 years ago
10

Question 12 (1 point)

Mathematics
1 answer:
Paraphin [41]3 years ago
4 0
<h3>Answer:   5</h3>

=================================================

Explanation:

Let's consider the expression (x-y)^2. It expands out to x^2-2xy+y^2. The terms are:

  • x^2
  • -2xy
  • y^2

Each of those terms either has a single variable with an exponent of 2, or has the exponents add to 2. Think of 2xy as 2x^1y^1.

In short, this means that the degree of each monomial term is 2.

----------

Now consider (x-y)^3. It expands out into x^3-3x^2y+3xy^2+y^3.

We have terms that either have a single variable and the exponent is 3, or the exponents add to 3. The degree of each term is 3.

----------

This pattern continues.

In general, for (x-y)^n, where n is any positive whole number, the degree of each term in the expansion is n. If you picked any term, added the exponents, then the exponents will add to n.

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Vesnalui [34]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{m = 9}}}}}

Option A is the correct option

Step-by-step explanation:

\sf{5m + 3m - 8 = 64}

Collect like terms

⇒\sf{8m - 8 = 64}

Move 8 to right hand side and change it's sign

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Calculate

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Instead, she should divide both sides by -4 to undo the multiplication. Specifically, the multiplication between the -4 term and the (x-2)^2 term.

This is one possible correction of what her steps could look like.

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In the third step, I'm dividing both sides by -4. In the sixth step, I'm applying the square root to both sides to undo the squaring operation. Then two steps later, I'm adding 2 to both sides to undo the "-2", which helps fully isolate x.

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