We need the actual problem/diagram or whatever to solve this
The angle here is an acute angle at ground level. Then the side adjacent to this angle is 126 feet. The opp. side is the tower, 111 feet tall.
Then
tan theta = opp / adj = 111 / 126. Using the inverse tangent function, we find that the measure of the angle is 0.722 radian or 41 degrees (to the nearest degree).
ANSWER: 24 people
All you have to do is multiply 25 and 6 to get 150. Then minus 150 from 385 to get 235. Then divide 235 by 10 to get 23.5, since you can not have half a person the answer is to round up to 24.
Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
Step-by-step explanation:
s = -4.9t² + 49t
The vertex of the parabola is at t = -b/(2a).
t = -49 / (2 × -4.9)
t = 5
The rocket reaches its maximum height after 5 seconds.
