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3 years ago

I’ll give brainliest!!! i just need the coordinates of T

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

3 0

Answer:

(-4, 5)

Step-by-step explanation:

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Sydney is going to a carnival that has games and rides. Each game costs $1.25 and each ride costs $2.25. Sydney spent $24.25 alt

Ede4ka [16]

She went on 8 rides and 5 games because 2.25*8=18 1.25*5=6.25
18.00+6.25=24.25 and 8-5=3.

8 0

3 years ago

The bill was $14.00. She left a 20% tip for the waitress. How much change did she get back from $20.00

drek231 [11]

20%=0.2
14*0.2 = 2.8 ( $2.80 is the tip she will be giving her)
$14+$2.80 = $16.80 ( what she will be giving in total)
$20-$16.80 = $3.20 (the change she will get back)

3 0

3 years ago

suppose you invest b$1000 in an account that guarantees an interest rate of 2.5% compounded daily. How much money would be in yo

Vesna [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

A store holiday sale has an item marked down by $10 with an additional discount of 25% off the

ValentinkaMS [17]

Answer:

C : $58.36

Step-by-step explanation:

Given:

A store holiday sale has an item marked down by $10.

Discount on new price = 25%

Final price was $36.27.

Question asked:

what was the original ?

Solution:

Let original price = $x$

New price = $x - 10$

Original price - marked down amount - discount amount = $36.27

$x - 10 -25\% of(x - 10 ) = 36.27\\$

$x - 10 - \frac{25}{100} (x - 10) = 36.27\\x - 10 - 0.25(x - 10) = 36.27\\x - 10 -0.25x +2.5 = 36.27\\0.75x - 7.5 = 36.27\\$

Adding both side by 7.5

$0.75x = 43.77\\$

Dividing both side by 0.75

$x = 58.36$

Therefore, the original price was $58.36

5 0

3 years ago

Maria drove to a business appointment at 50mph in the morning. Her average speed on the return trip in the afternoon was 40 mph.

MakcuM [25]

Answer:

Distance to appointment point = 5 miles

Step-by-step explanation:

Let s be the distance to the appointment point,

We have Maria drove to a business appointment at 50mph in the morning.

Time taken in the morning

$t_m=\frac{s}{50}=0.02s$

Her average speed on the return trip in the afternoon was 40 mph.

Time taken in the afternoon

$t_a=\frac{s}{40}=0.025s$

Given that the return trip took 1/4hr longer because of traffic.

That is

$t_a-t_m=\frac{1}{4}hr=0.025hr$

Substituting

$t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles$

Distance to appointment point = 5 miles

7 0

3 years ago