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3 years ago

8

HELP QUICK!! The stem-and-leaf plot shows data from a set of size 80. What are the median and mode of this set?

1 answer:

Ivahew [28]3 years ago

8 0

Answer:

A,

Step-by-step explanation:

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The mean midday temperature recorded in June in a city in South California is 36ºC, and the standard deviation is 3ºC. The numbe

Vsevolod [243]

Answer:

About 4 days

Step-by-step explanation:

Convert 39 and 42 degrees C to a z score and then use the z-table

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2 years ago

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Lois wants to send a box of oranges to a friend by mail. the box of oranges cannot exceed a mass of 10 kg. if each orange has a

-Dominant- [34]

No. of Oranges = Total Mass/Mass of one orange
IF only the mass of oranges is considered(not the box)

So, No. of oranges = 10*1000g/200g
= 50
So answer is 50 oranges.

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2 years ago

mr banks left work at 5 15 P.M it took him 1 1/4 hours to drive home . at what time did mr banks drive home? worth 22 points

Zepler [3.9K]

Using the information that you've provided, I would say that Mr. Banks drove home at 5:15, but if you're asking what time he arrived home that would be at 6:30. :))

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3 years ago

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Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

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3 years ago

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Use the distributive property to write an equivalent expression.<br> -(0-2)

Savatey [412]

Answer:

0+2 or simply 2

Step-by-step explanation:

just imagine a "1" by the minus

-1(0-2)

5 0

2 years ago