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Mashcka [7]
2 years ago
15

Stacy goes to the county fair with her friends . The total cost of ride tickets is given by the equation c=3.5t , where c is the

total cost of tickets and t is the number of tickets . If Stacy brought 15 tickets she would spend how much money ?
Mathematics
1 answer:
madreJ [45]2 years ago
3 0

Answer:

<h2><u>$52.5</u></h2>

Step-by-step explanation:

Step one:

given data

we are given that the linear function for the cost is  c=3.5t

c is the cost and

t is the number of tickets.

We are told that t=15, to find c, let us put the value of t in the linear function for the cost

c=3.5(15)\\\\c=52.5

<u>This shows that 15 tickets will cost $52.5</u>

<u />

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If cos θ = .62 and if 0&lt;θ&lt;90 what is the approximate value of sin θ to the nearest hundredth
Deffense [45]
\cos\Theta=0.62\\\\\text{Use:}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\Theta+(0.62)^2=1\\\\\sin^2\Theta+0.3844=1\ \ \ |-0.3844\\\\\sin^2\Theta=0.6156\to\sin\Theta=\pm\sqrt{0.6156}\\\\\sin\Theta_1\approx-0.78\ \vee\ \sin\Theta\approx0.78\\\\\Theta\in(0^o;\ 90^o),\ therefore\ \sin\Theta \ \textgreater \  0\to\boxed{\sin\Theta\approx0.78}
5 0
3 years ago
The proprietor of a boutique in New York wanted to determine the average age of his customers. A random sample of 25 customers r
jolli1 [7]

Answer:

28-2.064\frac{10}{\sqrt{25}}=23.872    

28+2.064\frac{10}{\sqrt{25}}=32.128    

So on this case the 95% confidence interval would be given by (23.9;32.1)  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=28 represent the sample mean

\mu population mean (variable of interest)

s=10 represent the sample standard deviation

n=25 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=25-1=24

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,24)".And we see that t_{\alpha/2}=2.064

Now we have everything in order to replace into formula (1):

28-2.064\frac{10}{\sqrt{25}}=23.872    

28+2.064\frac{10}{\sqrt{25}}=32.128    

So on this case the 95% confidence interval would be given by (23.9;32.1)    

7 0
3 years ago
PLEASE HELP
Taya2010 [7]

Answer:

In pictures

Step-by-step explanation:

By the way, question 2 is same as question 1

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3 years ago
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Vlad1618 [11]

Answer:

Arc JK: 27°

Arc NJ: 153°

Arc JL: 117°

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the answer to the equation 4a+26-9a-17=26?
podryga [215]
First you have to put all of your common numbers together. 4a and 9a go together. You then subtract those because 9 is negative (-9). Then you get -5a. Now move on to your other numbers. You have 26 and 17. 17 is negative as well (-17), so you subtract it from 26. That gives you 9.
Your new equation is -5a + 9 = 26
Now you subtract 9 from both sides. Your positive (+9) will cancel out with your negative (-9). Then subtract it from 26. 9 minus 26 is 17. 
Now your equation is -5a = 17
Since it's negative, you're going to add it (5) to both sides. 
Your 5's cancel out, and 17 + 5 is 22. 
a = 22
22 is the answer 

5 0
3 years ago
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