The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:
ΔABC ~ ΔDEF
Step-by-step explanation:
If the given triangles ΔABC and ΔDEF are similar,
Their corresponding sides will be proportional.

By substituting the measures of the given sides,

2 = 2 = 2
Since, corresponding sides of both the triangles are proportional, both the triangles will be similar.
ΔABC ~ ΔDEF
Answer:
Its 53 because 1=1 and 2=2
Step-by-step explanation:
Answer:
i dont get whats the question
Step-by-step explanation:
Answer:
There are 6 sandwich choices.
Step-by-step explanation:
2*3=6