Answer:
<h3>YES</h3>
Step-by-step explanation:
Given the position of the particle expressed using the expression;
x(t)= 5t^3 - 9t^2 + 7 where;
x moves along the positive x-axis
when t = 1
x(1) = 5(1)^3 - 9(1)^2 + 7
x(1) = 5 - 9 + 7
x(1) = -4 + 7
x(1) = 3
<em>Since the position of the particle is positive at t = 1, hence the particle is moving towards the right at time t = 1</em>
Answer:
y = -5/4x +1
Step-by-step explanation:
The slope-intercept form of a line is given by
y = mx + b where m is the slope and b is the y intercept
We are given the slope and a point on the line
y = -5/4 x + b
We can substitute the point for x and y and solve for b
-9 = -5/4(8)+b
-9 = -10+b
Add 10 to each side
-9+10=-10+10+b
1 = b
The slope intercept form of the equation is
y = -5/4x +1
Answer:
x = 10 cm, y = 5 cm gives a minimum area of 300 cm^2.
Step-by-step explanation:
V= x^2y = 500
Surface area A = x^2 + 4xy.
From the first equation y = 500/x^2
So substituting for y in the equation for the surface area:
A = x^2 + 4x * 500/x^2
A = x^2 + 2000/x
Finding the derivative:
dA/dx = 2x - 2000x^-2
dA/dx = 2x - 2000/x^2
This = 0 for a minimum/maximum value of A, so
2x - 2000/x^2 = 0
2x^3 - 2000 = 0
x^3 = 2000/ 2 = 1000
x = 10
Second derivative is 2 + 4000/x^3
when x = 10 this is positive so x = 10 gives a minimum value of A.
So y = 500/x^2
= 500/100
= 5.
Answer:
500
Step-by-step explanation:
I had the same question this week trust
