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d1i1m1o1n [39]
3 years ago
5

Drag each sequence to show whether it is a linear function, an exponential function, or

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

From the picture attached,

Option A

From the given table,

Ratio of the 2nd value and 1st value = \frac{8}{4}=2

Ratio of 3rd value and 2nd value = \frac{16}{8}=2

There is a common ratio of 2.

Therefore, the given table will represent an exponential function.

Option B

Given recursive formula of the sequence is,

A_1=3

A_n=5.A_{n-1}

From this recursive formula sequence will be,

3, 15, 75, 375,.......

Therefore, it's an exponential function.

Option C

F_n=3n+17

Given function is in the form of a linear function (y = mx + b),

Therefore, it's a linear function.

Option D

From the given table,

Difference between 2nd value to the 1st value = 8 - 4 = 4

Difference between 3rd value to the 2nd value = 12 - 8 = 4

Therefore, there is a common difference of 4 in each successive term to the previous term.

Hence, the given table represents a linear function.

Solnce55 [7]3 years ago
4 0

Answer:

above me will also work for problems in the photo below

Step-by-step explanation:

I did the problem

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Liam had $250. Then, he and his classmates bought a present for their teacher, evenly splitting the $p cost among the 24 of them
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Read 2 more answers
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
Two students are reading a novel. Ashley reads 10 pages per day. Carly reads 8 pages per day, but she starts
natulia [17]

Answer:

On day 20, they should both be on page 200

Step-by-step explanation:

I set the 2 equations up:

10d=8d+40 and then subtracted 8d from both sides

2d=40 and then divided both sides by 2

d=20

I then took 20 and multiplied it by 10 for Ashley (200) and then multiplied it by 8 for Carly (160) and added 40 (200)

Hope this helps!

3 0
3 years ago
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