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3 years ago

Worth 10 points ! need help asap

Mathematics

2 answers:

dusya [7]3 years ago

7 0

Answer:

second option

Step-by-step explanation:

You want to isolate the 'y' in each inequality:

4x - 5y ≤ 1

-5y ≤ -4x + 1

y ≥ 4/5x - 1/5 (inequality symbol changed because we divided by a negative)

1/2y - x ≤ 3

y - 2x ≤ 6 we multipled the original inequality by 2 to eliminate the denom.

y ≤ 2x + 6

harkovskaia [24]3 years ago

5 0

The answer would be the 2nd option

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Can you guys help me with this one, thanks

Fudgin [204]

Answer:

The answer is 3 3/4

Step-by-step explanation:

First, you have to find a common denominator. 4 and 6 both can first into 12, so 12 is the common denominator. Then you subtract.

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3 years ago

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Step-by-step explanation:

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3 years ago

The volume of a large aquarium is 210 yd. It is 3 yd wide and 2

Pavel [41]

Length of the aquarium is 35 yd

Step-by-step explanation:

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5 0

3 years ago

When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression? 10 x minus 25 y + 18 minus 25

yaroslaw [1]

Answer:

The answer to your question is 35x - 35y + 21

Step-by-step explanation:

Data

Simplify 0.5(20x - 50y + 36) - 0.25(-100x + 40y - 12)

Expand

10x - 25y + 18 + 25x - 10y + 3

Group like terms

(10x + 25x) + (-25y - 10y) + (18 + 3)

Result

35x - 35y + 21

The answer is the last choice

4 0

3 years ago

Read 2 more answers

Function rule and y intercept

stiks02 [169]

to get the equation for any straight line, all we need is two points from it, so hmmm say from this table let's use (2,0) and (6,-8)

$\bf \begin{array}{|r|r|r|r|r|r|} \cline{1-6} days&x&2&4&6&8\\ \cline{1-6} dollars&y&0&-4&-8&-12\\ \cline{1-6} \end{array}~\hfill (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{-8}{4}\implies \cfrac{\stackrel{rise}{-2}}{\underset{run}{1}}\implies \stackrel{slope}{-2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-2}(x-\stackrel{x_1}{2}) \\\\\\ \stackrel{~\hfill y-intercept}{y=-2x\stackrel{\downarrow }{+4}}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

6 0

4 years ago