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Rasek [7]
3 years ago
12

The equation T^2 = A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun,

A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?
Mathematics
1 answer:
Helen [10]3 years ago
4 0

So, let planet X's orbital period be T and its mean distance from the sun be A. Also let planet Y's orbital period be T_1, so that means if planet Y's mean distance from the sun were double that of planet X:

Z^2=(2A)^3\\ Z^2=8A^3\implies\\ Z^2=8T^2 \implies\\ Z=2\sqrt{2}T

Which means that the orbital period in planet Y is increased by a factor of 2\sqrt{2}

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{(1,0.5)(2,0.25)(3,0.125)(4,0.0625)} Which kind of model best describes the data set?
Kazeer [188]

Answer:

  exponential: y = 2^(-x)

Step-by-step explanation:

The y-differences are not constant, and the x-y products are not constant. For each increase in x, y is divided by 2, so this is a geometric sequence that can be described by an exponential model. The common factor is 1/2.

A simple way to write the model for this is ...

  y = 2^(-x)

5 0
3 years ago
The following table lists the masses, in grams, of the nine planets (including dwarf planet Pluto). Use the data to choose the c
Marrrta [24]

The ratio between the masses of Jupiter and Venus is

\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}

We can separate the coefficient and the powers of ten:

\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}=\dfrac{1.989}{4.869}\cdot \dfrac{10^{30}}{10^{27}}

Use the exponent rule

\dfrac{a^b}{a^c}=a^{b-c}

to simplify the powers of 10:

\dfrac{10^{30}}{10^{27}}=10^3

So, the ratio is

\dfrac{1.989}{4.869}\cdot 10^3\approx 0.4\cdot 10^3=400

So, Jupiter has a mass that is approximately 400 times greater than Venus's.

4 0
3 years ago
Read 2 more answers
Write the polar equation 0= pi/3
densk [106]

Answer:

1

(

π

3

)

)

Step-by-step explanation:

Explanation:

Substitute

tan

(

y

x

)

for

θ

tan

(

y

x

)

=

π

3

Obtain

y

x

on the left by using the inverse tangent on both sides:

tan

−

1

(

tan

(

y

x

)

)

=

tan

−

1

(

π

3

)

y

x

=

tan

−

1

(

π

3

)

Multiply both sides by x:

y

=

(

tan

−

1

(

π

3

)

)

x

4 0
2 years ago
4. Suppose an investment of $s1.800 doubles in value every 7 years. How much is the investment worth after 42 years?
igor_vitrenko [27]

we are given

initial amount =1800

so,

P=1800

doubles in value every 7 years

so, we can find function

A=P(2)^{\frac{t}{7} }

now, we can plug P=1800

A=1800(2)^{\frac{t}{7} }

now, we can plug t=42

A=1800(2)^{\frac{42}{7} }

A=115200.............Answer

6 0
3 years ago
Amy graphed a point to represent the absolute value of a number on a number line. If the original number is less than -10, descr
Lilit [14]

Absolute value of any number is always positive because absolute value is represent distance and distance will be always positive.

Since, Absolute value of any number is always positive because absolute value is represent distance and distance will be always positive.

So, absolute value of -11 is 11 , It means that on number line graph -11 is 11 unit left of zero.

Similarly,  absolute value of -12 is 12 and it means that -12 is 12 unit left from zero.

Learn more:

brainly.com/question/12928519

4 0
2 years ago
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