Answer:
b
Step-by-step explanation:
Answer:
Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.
Step-by-step explanation:
Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.
Answer:
The correct option is B) Deletes the table structure along with the table data.
Step-by-step explanation:
Consider the provided information.
The SQL DROP TABLE statement is used to delete a table description and all the requirements for that table of data, indexes, triggers, constraints and permissions.
Therefore, the correct option is B) Deletes the table structure along with the table data.
Answer:
2x (2x^2 +x +1)
Step-by-step explanation:
f(x)-g(x)
9x^3 + 2x^2 -5x + 4 - (5x^3 -7x +4)
9x^3 + 2x^2 -5x + 4 - 5x^3 +7x -4
4x^3 +2x^2 +2x
2x (2x^2 +x +1)
The solution is when x= 1
Hope this helps!