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Sauron [17]
3 years ago
12

Can y’all help me on 22 and 23

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

problem 22: 6

problem 23: 588,409

Step-by-step explanation:

for the first one, just divide 3600 by 585. it turns out to be a fraction, so you have to use the whole number that comes before all of the numbers behind the decimal. and for the second one, it's just simple long division.

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If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

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i think this may help you

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