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DerKrebs [107]
3 years ago
14

150 = 8x + 6y solve for X ​

Mathematics
2 answers:
Dominik [7]3 years ago
8 0

Answer:

y=25

Step-by-step explanation:

150=8x+6y

150=8(0)+6y

150=6y

divided by 6 on both sides because what you do to one side you have to do to the other side.

then your left with y=25

ki77a [65]3 years ago
8 0

Answer:

Simplifying

150 = 8x + 6y

Solving

150 = 8x + 6y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.

150 + -8x = 8x + -8x + 6y

Combine like terms: 8x + -8x = 0

150 + -8x = 0 + 6y

150 + -8x = 6y

Add '-150' to each side of the equation.

150 + -150 + -8x = -150 + 6y

Combine like terms: 150 + -150 = 0

0 + -8x = -150 + 6y

-8x = -150 + 6y

Divide each side by '-8'.

x = 18.75 + -0.75y

Simplifying

x = 18.75 + -0.75y

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

3 0
3 years ago
please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.
likoan [24]

ANSWER:

\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4

STEP-BY-STEP EXPLANATION:

We have the following equation:

f(x)=\sqrt{x}-4

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\  \\ \sqrt{f^{-1}(x)}=x+4 \\  \\ f^{-1}(x)=(x+4)^2 \end{gathered}

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4

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1 year ago
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kifflom [539]

Answer:

385/500

Step-by-step explanation:

this is the answer I'm pretty sure about it.

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Step-by-step explanation:

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