So the general formula for compound interest is $A = P(1+\frac{r}{n})^{nt}$ where r is the interest rate, t is the time in years, and n is the amount of compounds per year. So plugging in the values for both equations you'll get

Opportunity Loans:

$A = 1600(1+\frac{0.0345}{12})^{(12)(1)}$

$A = 1600(1.002875)^{12}$

$A \approx 1600(1.035)$

$A = \$1,656.08$

Now to find the interest accrued on this loan you simply subtract 1600 from the A or final amount

$Interest=1656.08-1600\\Interest=56.08$

General Loans:

$A = 1600(1+\frac{0.042}{4})^{(4)(1)}$

$A = 1600(1.0105)^4$

$A \approx 1600(1.042)$

$A = 1,668.27$

To find the interest we do the same thing we did in the previous problem

$interest = 1668.27-1600\\interest=68.27$

Opportunity loans has the least amount of interest after a year

8 0

2 years ago

2(p+7)=18<br><br>Please add a equation

Aleonysh [2.5K]

Answer: P = 2

Step-by-step explanation:

18 = 2(p+7)

18 = 2(2P+14)

-14 -14

4 = 2P

2=P

7 0

3 years ago

What is the equation in slope intercept form of the perpendicular bisector of the given line segment?

andreev551 [17]

Answer:

y = -4x - 6

Step-by-step explanation:

The equation of a line in point-slope form.

$y - y_1 = m(x - x_1)$

is the equation of the line containing point (x1, y1) and having slope, m.

The given point of the perpendicular bisector is (-1, -2), so in this case, x1 = -1, and y1 = -2.

We need the slope of the perpendicular bisector. First we find the slope of the segment. We start at point (-5, -3). We go up 1 unit and 4 units to the right, and we are at another point on the segment. Since slope = rise/run, the slope of the segment is 1/4. The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular bisector is the negative reciprocal of 1/4, so for the perpendicular bisector, m = -4.

Now we use the equation above and our values.

$y - y_1 = m(x - x_1)$

$y - (-2) = -4(x - (-1))$

$y + 2 = -4(x + 1)$

$y + 2 = -4x - 4$

$y = -4x - 6$

6 0

3 years ago