The other diagonal would be 13 feet as well because it is a rectangle.
Answer:
no
Step-by-step explanation:
most people go through mid school cheating
Answer:
Largest possible length is <em>21 inches</em>.
Step-by-step explanation:
Given:
Total material available = 60 inches
Length to be 3 more than twice of width.
To find:
Largest possible length = ?
Solution:
As it is rectangular shaped frame.
Let length =
inches and
Width =
inches
As per given condition:
..... (1)
Total frame available = 60 inches.
i.e. it will be the perimeter of the rectangle.
Formula for perimeter of rectangle is given as:

Putting the given values and conditions as per equation (1):

Putting in equation (1):

So, the answer is:
Largest possible length is <em>21 inches</em>.
Answer:
105.12 ft^2
Step-by-step explanation:
Area of a rectangle: bh
In this case 8*10.... so area of the rectangle is 80
Area of a circle: pir^2
Half it for a semicircle.
so 1/2 pi r^2
radius is 4 cuz its half of 8.
so 1/2(3.14)(4^2)=(0.5)(3.14)(16)=25.12
Now add up 80+25.12
Total is 105.12
Hope I helped :)
9x9 = 81
So, the answer would be 81 inches squared