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3 years ago

Which city did Miss Hill move to with her new husband?

Mathematics

1 answer:

zubka84 [21]3 years ago

3 0

Miss Hill moved to Chicago.
Hope this helps!!
Please give brainliest if it’s correct!

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Factor completly x^2 -64

Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

$\left(x+8\right)\left(x-8\right)$

Step-by-step explanation:

⇒ Given info:

Factor completely $x^2 -64$

⇒ Solution:

Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.

$=x^2-8^2$

Applying difference of two squares formula: $x^2-y^2=\left(x+y\right)\left(x-y\right)$

$=x^2-8^2=\left(x+8\right)\left(x-8\right)\\$

$=\left(x+8\right)\left(x-8\right)$

Answer~: $\left(x+8\right)\left(x-8\right)$

xcookiex12

8/19/2022

7 0

2 years ago

An opera house has a seating capacity of 872 people with each ticket costing 50 Rupees .If the opera house is running for 15 day

Nataly_w [17]

Answer:

654000 Rupees

Step-by-step explanation:

If we assume that the opera house was full every day then it would be 872 x 50 for the price of 1 day

872 x 50 = 43600

We multiple that number by the amount of days open so is would be 43600 x 15

43600 x 15 = 654000

Therefore it will make 654000 Rupees

7 0

3 years ago

In right triangle ABC, ZC is a right angle, m ZA = 52, AC = 10.01, and AB = c.

nlexa [21]

Answer:

The measurement of AB is 16.25 units.

Step-by-step explanation:

In right triangle ABC, ∠C is a right angle, m∠A = 52° , AC = 10.01, and AB = c.

We need to find the measurement of AB.

∠C is a right angle, it means AB is hypotenuse.

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos A=\dfrac{AC}{AB}$

$\cos (52^\circ)=\dfrac{10.01}{c}$

$0.616=\dfrac{10.01}{c}$

$c=\dfrac{10.01}{0.616}$

$c=16.25$

Hence, the measurement of AB is 16.25 units.

6 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

4 years ago

Fill in the blank to make the statement true (-2+6)+__=-2+[6+(-8)

bixtya [17]

Answer:

-8

Step-by-step explanation:

you have to make them equivalent so and the one thing missing from the other side of the equation

4 0

3 years ago