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Sauron [17]
3 years ago
9

8)

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

the answer is 0 because both equations on either side cancel out thereby leaving in bare

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Let p(x) be a polynomial, and suppose that a is any real number. Prove that

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Solution. Notice that

 

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

 

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Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

 

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

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= 40

 

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fjhrhgvfj

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