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LenKa [72]
3 years ago
13

The radius of a circle is

Mathematics
1 answer:
KIM [24]3 years ago
7 0

Answer:

43.98

Step-by-step explanation:

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Convert to quarts: 10 pints
Ad libitum [116K]

Answer:

B

Step-by-step explanation:

Pints and Quarts are measures of volume. The relationship between them is rather simple.

We know 2 pints = 1 Quart

The problem gives us the number of pints and we need to find the number of quarts. From the relationship, we see that "pints divided by 2 will give us quarts"

Given >> 10 pints

Hence, number of quarts would be 10/2 = 5

Hence 10 pints = 5 quarts

Answer choice B is right.

8 0
4 years ago
There was a Rockets game on Friday and Saturday.
katrin [286]
18,055
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3,138
———-
14,927

14,927
+
18,055
———-
32,982
6 0
3 years ago
Read 2 more answers
A person invests 9000 dollars in a bank. The bank pays 4.25% interest compounded daily. To the nearest tenth of a year, how long
mezya [45]

Answer:

The person must invest the money in the bank for 18 years to reach $19600, if a person invests 9000 dollars in a bank and the bank pays 4.25% interest compounded daily.

Step-by-step explanation:

4 0
3 years ago
What value can be written on the blank line to make the expressions equivalent?
KIM [24]
Hello!

I believe the number that can be written in the blank space above is 6.

48+54=6'(8+9)

The number written in the blank space is 6 because when you divide 48 and 54 by their numbers, 8 and 9, you will get an answer of 6 for both numbers.

48/8=6
54/9=6

So the number in the blank space would be 6.

I hope this helps!
3 0
4 years ago
Read 2 more answers
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

x_{2} = 3

Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

7 0
4 years ago
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