Answer:

Step-by-step explanation:
Let <em>P(A) </em>be the probability that goggle of type A is manufactured
<em>P(B) </em>be the probability that goggle of type B is manufactured
<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.
According to the question,
<em>P(A)</em> = 30%
<em>P(B)</em> = 70%
<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.
P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.
will be the probability that a goggle is of type A and is returned within 10 days of its purchase.
will be the probability that a goggle is of type B and is returned within 10 days of its purchase.





If a goggle is returned within 10 days of its purchase, probability that it was of type B:


So, the required probability is 
Answer:
The y-value is -20
Step-by-step explanation:
So let's solve this by Elimination method;
-2(4x + 5y = -12)
4(2x + 3y = -16)
Let's Distribute;
-8x - 10y = 24
8x + 12y = -64
So x cancels out because -8 + 8 = 0
-10y + 12y = 2y
24 - 64 = -40
2y = -40
Divide both sides by 2;
y = -20
Now lets plug in y to find the value of x;
4x + 5(-20) = -12
4x - 100 = -12
Add 100 to both sides;
4x = 88
Divide both sides by 4;
x = 22
we have the function

For x=2
substitute

therefore
<h2>the answer is 4.20 million dollars</h2>
(number less tan 10 and more than or equal to 1) times (10^m)
0.00048=4.8 times 10^4
answer si 4.8*10^4