Answer:
Therefore to prove that ABCD is a parallelogram we need,
BK = DK
CK = AK
Step-by-step explanation:
Given:
The diagonals of quadrilateral ABCD , intersect at point K.
To Find:
Which statement needed to prove that ABCD is a parallelogram?
Solution:
For a Quadrilateral to be a Parallelogram,
- Diagonals Bisect each other.
- Opposite Sides are Parallel and Equal.
- Opposite angles are equal.
Here Diagonals intersect at K
∴ BK = DK ......K bisect Diagonal BD
∴ CK = AK ......K bisect Diagonal AC
Therefore to prove that ABCD is a parallelogram we need,
BK = DK
CK = AK
Answer:
1, 3
Step-by-step explanation:
I took the test
Answer:
Then what is the radius of the circle? Since, the tangent of any point of a line is perpendicular to the radius through the point of contact. Hence, radius of the circle = 8 cm.
This will come to 0.55*7 = $3.85
You would save $3.85
You would divide the two numbers to get 54