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Nataly_w [17]
3 years ago
13

3

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

B

D

A

Step-by-step explanation:

Given:

A. 2x^3-x^{2} -6x

B. 2x^3+8x+4

C. 3x^4+x^{2} +x-7

D. 3x^4-3x^{2} +5x-7

Now, let us evaluate the given expressions one by one.

(4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4

It is equation B.

So, (4x^3-4+ 7x)-(2x^3-x-8) is equivalent to B.

(-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7

It is equation D.

So, (-3x^2+x^4+x)+(2x^4-7+4x)  is equivalent to D.

(x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x

It is equation A.

So, (x^{2} -2x)(2x+3) is equivalent to A.

So, answer is:

B

D

A

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