Circumference=2pi*r
20.7=2pi*r
r=3.296 or 3.3
A=pir^2
a=34.1946 or about 34.19
Answer:
D. -6m²n² + 10m²n + 8mn² - 10mn
Step-by-step explanation:
(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)
Apply the distributive property to remove the parentheses
-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn
Combine like terms together and arrange in standard form
-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn
-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn
-6m²n² + 10m²n + 8mn² - 10mn
Answer:
t = -1/8.
Step-by-step explanation:
t / 5/12 = -3/10 Invert the 5/12 and multiply:
12t / 5 = -3/10
Cross multiply:
12t * 10 = 5 * -3
120t = -15
t = -15/120 = -1/8.
So,
2.11 can be written as 2 and 11 hundredths, or

.

is in simplest form.
Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6
Or uniform acceleration, a = - 1.6
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:



