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notsponge [240]
2 years ago
9

What is the answer to y the in the problem 8y+y=63

Mathematics
1 answer:
GuDViN [60]2 years ago
3 0

Answer:

y=7y=7y=7

Step-by-step explanation:

How to solve your question

Your question is

8+=63

8y+y=638y+y=638y+y=63

Solve

1

Combine like terms

8+=63

8y+y=63{\color{#c92786}{8y}}+{\color{#c92786}{y}}=638y+y=63

9=63

9y=63{\color{#c92786}{9y}}=639y=63

2

Divide both sides of the equation by the same term

3

Simplify

Solution

=7

y=7y=7y=7

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RUDIKE [14]
1) cf= 24 hours/1 day, 1 hour/60 minutes
30 x 1/60 = .5
10 x 24/1 = 240
240 + .5 = 240.5 hours

2) cf = 24 hours/1 day, 60 minutes/1 hour, 12 inches/1 foot
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4 0
3 years ago
Find the area of the figure. I will make you a brainllest:)
dusya [7]

Answer:

70

Step-by-step explanation:

A=a+b

2h=8+12

2·7=70

6 0
3 years ago
Which one of the following is an example of a repeating decimal A. 0.666666 B. 1.234545 C. 6.787878 D.0.123321
sweet [91]
The answer: A. 0.666666
4 0
3 years ago
What is the perimeter of parallelogram HIJK? Round to the nearest hundredth.
bixtya [17]

Answer:

Perimeter of the parallelogram = 26.64 units

Step-by-step explanation:

The perimeter of parallelogram = 2(a + b)

Here a = KJ = 7 units.

b = HK

We need to find the HK using the distance formula.

Distance formula = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

H = (-4, 3) and k = (-2, -3)

Now plug in x1 = -4, y1 =3, x2 = -2, y2 = -3 in the distance formula

HK = \sqrt{(-2 -(-4))^2 + (-3 - 3)^2}

= \sqrt{(-2 +4)^2 + (-6)^2}

= \sqrt{4 + 36}

= \sqrt{40}

HK = b = 6.32 units

Now plug in a = 7 and b = 6.32 in the perimeter formula, we get

Perimeter = 2(7 + 6.32)

= 2(13.32)

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Thank you.

6 0
3 years ago
Write the common rule to describe the translation using coordinate notation.
UNO [17]

The common rule is (x - 1, y + 3) can be used to describe the translation.

Step-by-step explanation:

Step 1:

The point J (-3, -4) becomes J^{1} (-4, -1).

In order to write the rule for translation from J to J^{1}, we subtract the x coordinate of J from J^{1} and subtract the y coordinate of J from J^{1}.

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The y coordinate = -1-(-4) = -1+4 = 3.

Step 2:

So from the calculations, we get that the x coordinate is subtracted by 1 i.e. x-1 and the y coordinate is increased by 3 i.e. y+3.

So the common rule is (x - 1, y + 3).

4 0
3 years ago
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