The first question would be distance from the start, as it is steadily going up as time goes on.
The second question would be distance from the end, as it is steadily going down as time goes on.
The third question would be speed, as the speed is staying stable as shown by the straight lines seen within the distance from start/end graphs being linear lines.
Take $1.75 from the $10 then dived the 55cents into the sum. Thus $10 - $1.75 = $8.25. / .55 =15 miles exactly
Answer:
312
Step-by-step explanation:
its easy
Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
