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GaryK [48]
2 years ago
7

2(4x+3)>-10 or -5x-15>5

Mathematics
1 answer:
bezimeni [28]2 years ago
8 0
I don’t really understand but this are the answer for both the first one: x>-2 second: x<-2
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The perimeter of parallelogram WXYZ is 50 millimeters. What is WX?
garri49 [273]

Answer:Wx = − 50 m 2 l 2 t e 2 r s

Step-by-step explanation:

4 0
3 years ago
1/3 times 3/4 times 1/3 as a fraction so basically what is 0.08333333333 as a fraction
SpyIntel [72]

Answer:

mark me brainliest

Step-by-step explanation:

To write 0.08333333333 as a fraction you have to write 0.08333333333 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.08333333333 = 0.08333333333/1 = 0.8333333333/10 = 8.333333333/100 = 83.33333333/1000 = 833.3333333/10000 = 8333.333333/100000 = 83333.33333/1000000 = 833333.3333/10000000 = 8333333.333/100000000 = 83333333.33/1000000000 = 833333333.3/10000000000 = 8333333333/100000000000

And finally we have:

0.08333333333 as a fraction equals 8333333333/100000000000

7 0
2 years ago
Read 2 more answers
Please help ♡♡♡♡♡♡♡​
lions [1.4K]

Step-by-step explanation:

\angle AOB and \angle BOC are linear pair angles.

\therefore m\angle AOB + m\angle BOC = 180° \\  \therefore  \: 3x + 124 \degree + 6x + 29 \degree  = 180° \\  \therefore  \: 9x  + 153 \degree  = 180°  \\ \therefore  \: 9x  = 180°  - 153 \degree   \\ \therefore  \: 9x  = 27 \degree   \\ \therefore  \:x =  \frac{27 \degree }{9}  \\  \huge \pink{ \boxed{\therefore  \:x =3 \degree }} \\  \\  \because \: m\angle BOC =6x + 29 \degree   \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree   \\ \therefore \: m\angle BOC = 18\degree + 29 \degree    \\ \\   \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree   }}

5 0
3 years ago
700 is 2 parts in the ratio 3:2, how much would 3 parts be?
Ad libitum [116K]

answer:

3 parts will be 420

explanation:

total ratio: 3 + 2 = 5

5 ➳ 700

1 ➳ 700/5

1 ➳ 140

solve for 3 : 2

3 ➳ 140 * 3 = 420

2 ➳ 140 * 2 = 280

5 0
2 years ago
Read 2 more answers
In the expression (ax+b)*(cx^2+dx+e), find two set of values of a,b,c,d and e so that the coefficient of x^3and x terms after ex
Brilliant_brown [7]

Answer:

2, 0, 2, 3, 5

1, 2, 4, 0, 5

Step-by-step explanation:

(ax + b)(cx² + dx + e)

acx³ + adx² + aex + bcx² + bdx + be

2(2)x³ + 2(3)x² + 2(5)x + 0 + 0 + 0

4x³ + 6x² + 10x

a = 2

b = 0

c = 2

d = 3

e = 5

1(4)x³ + 1(0)x² + 1(10)x + 2(4)x² + 0 + 10

4x³ + 8x² + 10x + 10

a = 1

b = 2

c = 4

d = 0

e = 5

7 0
2 years ago
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