All this means is (f(x)) + (g(x))
2x-1+ x^2-3x-2=
=== x^2 - x -3
Hope it helps.....................
MrBillDoesMath!
Answer to #4: 81/256 * s^8 * t^ 12
Comments:
(7x^3) ^ (1/2) = 7 ^ (1/2) * x^(3/2) where ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.
---------------------
(1) (27s^7t^11)^ (4/3)
= 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)
As 27 = 3^3, 27 ^(4/3) = 3^4 = 81
(2) (-64st^2)^ (4/3) = (-64)^(4/3) * (s^4/3) * t(^8/3)
As 64 = (-4)^3, (-64)^(4/3) = (-4)^4 = +256
So (1)/(2) =
81 * s^(28/3)* t^(44/3)
------------------------------- =
256 s^(4/3) * t^((8/3)
81/256 * s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =
81/256 * s^(24/3) * t (36/3) =
81/256 * s^8 * t^ 12
MrB
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Answer:
(x, y) --> (x + 14, y + 8)
Step-by-step explanation:
Look at 1 original point and its corresponding translated point.
Let's look at F and F'.
To go from F to F', you need to go right in x 14 units.
Then you need to go up in y 8 units.
The translation rule is to add 14 to x and 8 to y.
(x, y) --> (x + 14, y + 8)
