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EastWind [94]
3 years ago
12

A rotating wind turbine has a diameter of about 145 feet and its circumference is about 456 feet. A smaller model of the turbine

has a circumference of about 16 feet. What will the diameter of the model be? If necessary, round to the nearest whole number.
The diameter of the model will be about ___ feet
Mathematics
2 answers:
Serjik [45]3 years ago
7 0

Answer:

ross-multiplication.

circumference divided by the diameter

10/x = 580/185

10x185=1850

1850/580=3.189

Step-by-step explanation:

give me brainliest

natulia [17]3 years ago
7 0

Answer:

7 feet.

Step-by-step explanation:

<u>Solve</u>

  • Set up a proportion using the given information for the turbine and its model.

C /d =  

C /d

  • Set up a proportion.

660 /210 =  

22/ d

  • Substitute the given values.

660 ÷ 30

210 ÷ 30  ≈  

22/ d

Since 660 divided by 30 is approximately 22, divide 210 by 30 to find the value of d.

660 /210  ≈  

22/ 7

 d ≈ 7

The diameter of the model is approximately 7 feet.

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strojnjashka [21]

Answer:

24 monkeys are in the tree

Step-by-step explanation:

We solve it by writing \frac{60}{100} times \frac{40}{1}

Why is it over 100? Because every percent is out of 100!

\frac{60}{100} X \frac{40}{1} (your equation)

60 times 40 = 2400 and 100 times 1 = 100, We get, \frac{2400}{100},

Lastly, we simplify the fraction by 100 on each side:

\frac{2400}{100} / \frac{100}{100}

you get 24

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The diagram shows one way to develop the formula for the area of a circle. Pieces of a circle with radius r are rearranged to cr
podryga [215]

Question:

a. A = (2πr)(r)

b. A = (2πr)(2r)

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Answer:

The correct option is A =\frac{1}{2} (2\pi r)(r)

Step-by-step explanation:

The formula for the area, A of a parallelogram = base, b × height, h

Therefore, since the base dimension is approximately half the perimeter of a circle, we have;

Base, b = 2·π·r × 1/2

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Therefore, the approximate area, A of the parallelogram is given by the following relation;

A = b × h =  2·π·r × 1/2 × r Which is the same as A = \frac{1}{2} (2\pi r)(r).

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