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Brums [2.3K]
3 years ago
13

Which multiplication has a negative answer?

Mathematics
2 answers:
Nataly_w [17]3 years ago
8 0

i'm pretty sure it's C

-1 times -1 becomes positive, and then times -1 again, it's negative, and times it again, it's positive, and <em>THEN</em> one more time (lol) it's -1.

Mila [183]3 years ago
7 0
The correct answer is D


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Arisa [49]

Answer:

[(pq,dc) (rs,ab)(ad,rq)(bc,sq)corosponding sides]

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2 years ago
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tresset_1 [31]

Answer:

  • m = -3/4
  • y-intercept = 399
  • slope-intercept equation: y = -3/4x + 399

Step-by-step explanation:

It can be easiest simply to solve the equation for y.

  3x + 4y = 1596

  4y = -3x + 1596 . . . . subtract 3x

  y = -3/4x + 399 . . . . divide by 4

From this equation in slope-intercept form you can read the slope as -3/4 and the y-intercept as 399. You already know the equation.

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3 years ago
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riadik2000 [5.3K]
I have worked out the answer to the question, I hope it helps you. Please do not forget to check if this answer if reliable, I am not always correct

8 0
2 years ago
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A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r
ohaa [14]

Answer:

b=2\frac23\:\sf ft

Area of triangle = 4 ft²

Area of rectangle = 6\frac23\: \sf ft^2

Area of irregular figure = 10\frac23\: \sf ft^2

Step-by-step explanation:

\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}

\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}

\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}

\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}

5 0
2 years ago
Read 2 more answers
Domain and range of the inequality y&lt;√x+3 +1
Margaret [11]

The domain of the given inequality is y>1.

<h3>What is Inequality?</h3>

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Here, given inequality:

              y < \sqrt{x+3}+1

Related equation:

             y = \sqrt{x+3}+1

The equation defined as,

    x+3 > 0

    x > -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

    \sqrt{x+3} \geq 0

adding 1 on both sides, we get

  \sqrt{x+3} + 1 \geq  1

      y ≥ 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

Thus, the domain of the given inequality is y>1.

Learn more about Inequality from:

brainly.com/question/20383699

#SPJ1

6 0
2 years ago
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