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2 years ago

Which number sentence is true?

Mathematics

1 answer:

Artemon [7]2 years ago

5 0

Answer:

yes

Step-by-step explanation:

but really nice to the world I'm happy for you because you is so buetiful

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Suppose a coin is flipped and a card is drawn from the deck. What is the probability that the coin lands on tails and the card i

Deffense [45]

Answer:

1/26

Step-by-step explanation:

1 out of 13 would be equal to the amount of cards that would be a jack.

But you also have to take into regards the coin flip 50%chance so you would just could what the number is divided by to get the right answer. Since out come could be tails or head instead of just being one for sure for example.

5 0

3 years ago

Pls help bond maths

zepelin [54]

Answer:

19) 35

20) 38

21) 36

22) 37,800

23) 2,450

24) 47

25) 25,000

26) 820

6 0

3 years ago

Read 2 more answers

In the accompanying diagram, lines a and b are parallel, and lines c and d are transversals. 5 a 6 3 4 7/8 be Which angle is con

OLga [1]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find all roots: x^3 + 7x^2 + 12x = 0 Show all work and check your answer.

Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

Solution:

We have been given a cubic polynomial.

$x^{3}+7 x^{2}+12 x=0$

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

$x^{3}+7 x^{2}+12 x=0$

$x\left(x^{2}+7 x+12\right)=0$ ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

$x^{2}+7 x+12=0$

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

Therefore, the two roots are:

$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

And,

$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0

3 years ago

Why does each number only have one square root?

Tamiku [17]

Answer:

it gets multiplied by the value of the root .that is just more concise way of writing it .

Step-by-step explanation:

3 0

3 years ago