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3 years ago

13

(Giving brainliest because I tried to solve this but I can’t for some reason)

2 answers:

CaHeK987 [17]3 years ago

6 0

Answer:

mean is 5

Step-by-step explanation:

AURORKA [14]3 years ago

5 0

Answer:

5 is the answer

Step-by-step explanation:

You might be interested in

What is the slope-intercept form of linear equations?

lara31 [8.8K]

to get the equation of any straight line, we simply need two points off of it, let's use the points from the picture below.

$(\stackrel{x_1}{8}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{12}-\underset{x_1}{8}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{8}) \\\\\\ y-3=\cfrac{1}{2}x-4\implies y=\cfrac{1}{2}x-1$

if we already have the slope, and we can see the y-intercept on the table, then we can simply use the slopel-intercept form and plug both of them in.

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \begin{array}{|c|ll} \cline{1-1} slope\\ \cline{1-1} \cfrac{1}{2}\\ \cline{1-1} y-intercept&\\\cline{1-1} (0~~,~~-1)\\ \cline{1-1} \end{array}~\hfill y=\cfrac{1}{2}x-1$

6 0

3 years ago

For 7 and 8, find the maximum or minimum point of the parabola

Leni [432]

Answer: 7) Max: y = 52

8) Min: y = -51

<u>Step-by-step explanation:</u>

The Max/Min is the y-value of the intercept.

Max is when the a-value is negative.
Min is when the a-value is positive.

First, find the x-value of the vertex using the Axis of Symmetry formula:

x = -b/2a. Then plug the x-value into the equation to find the y-value.

7) y = -2x² - 16x + 20

↓ ↓ ↓

a= -2 b= -16 c=20

$\text{AOS:}\quad x=\dfrac{-b}{2a}\quad =\dfrac{-(-16)}{2(-2)}\quad =\dfrac{16}{-4}\quad =-4$

Max: y = -2(-4)² - 16(-4) + 20

= -2(16) + 64 + 20

= -32 + 84

= 52

*********************************************************************************************

7) y = x² + 12x - 15

↓ ↓ ↓

a= 1 b= 12 c= -15

$\text{AOS:}\quad x=\dfrac{-b}{2a}\quad =\dfrac{-(12)}{2(1)}\quad =\dfrac{-12}{2}\quad =-6$

Max: y = (-6)² + 12(-6) - 15

= 36 - 72 - 15

= 36 - 87

= -51

8 0

3 years ago

1.Below are the scores from team Mexico in the women’s swim team competition. Mexico received a score from seven judges in diffe

Vera_Pavlovna [14]

Answer:

Mexico's total score was 49

The overall average was 7

Step-by-step explanation:

7.5+6.4+9.1+5.4+5.4+6.2+9.0=49

49/7=7

4 0

3 years ago

The area of a square floor on a scale drawing is 64 square centimeters, and the scale drawing is 1 centimeter:3 ft. What is the

Oxana [17]

Answer:

Part a) The area of the actual floor is $576\ ft^{2}$

Part b) The ratio of the area in the drawing to the actual area is $\frac{1}{9}\frac{cm^{2}}{ft^{2}}$

Step-by-step explanation:

we know that

The scale drawing is $\frac{1}{3}\frac{cm}{ft}$

step 1

Find the dimensions of the square on a scale drawing

The area of a square is equal to

$A=b^{2}$

where

b is the length side of the square

$A=64\ cm^{2}$

so

$64=b^{2}$

$b=8\ cm$

step 2

Find the dimensions of the actual floor

Divide the length of the floor on the drawing by the scale drawing

$8/(1/3)=24\ ft$

step 3

Find the area of the actual floor

The area of a square is equal to

$A=b^{2}$

substitute

$A=24^{2}=576\ ft^{2}$

step 4

Find the ratio of the area in the drawing to the actual area

$\frac{64}{576}\frac{cm^{2}}{ft^{2}}$

Simplify

Divide by 64 both numerator and denominator

$\frac{1}{9}\frac{cm^{2}}{ft^{2}}$

3 0

3 years ago

Please help!! ;w; Thank you in advance!!!

Dovator [93]

10 5/6 = 65/6

2 1/4 = 9/4

2 (9/4) = 9/2

So the length left is

65/6 - 9/2 =

65/6 - 27/6 =

38 / 6 =

19 / 3 =

6 1/3 in

sorry this was a late response

5 0

3 years ago