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levacccp [35]
3 years ago
14

Please help!! ;w; Thank you in advance!!!

Mathematics
1 answer:
Dovator [93]3 years ago
5 0

10  5/6  =   65/6

2  1/4    =  9/4

2 (9/4)  =   9/2

So   the  length  left   is

65/6  -  9/2    =

65/6  -  27/6   =

38 / 6    =

19 / 3    =

6 1/3   in

sorry this was a late response

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22848 is your answer after you subtract the interest rate

Step-by-step explanation:


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Write f(x)=8x^2-4x+11 in vertex form
Vlad [161]

Answer:

f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2}

or

f(x)=8(x-0.25)^{2}+10.5

Step-by-step explanation:

we have

f(x)=8x^{2}-4x+11

This is a vertical parabola open upward (because the leading coefficient is positive)

The vertex is a minimum

Convert to vertex form

Factor the leading coefficient

f(x)=8(x^{2}-\frac{1}{2}x)+11

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+11-\frac{1}{2}

f(x)=8(x^{2}-\frac{1}{2}x+\frac{1}{16})+\frac{21}{2}

Rewrite as perfect squares

f(x)=8(x-\frac{1}{4})^{2}+\frac{21}{2} ----> equation in vertex form

or

f(x)=8(x-0.25)^{2}+10.5

The vertex is the point  (0.25,10.5)

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9 less than a number can be written as
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9 less can be written as -9

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Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
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