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JulijaS [17]
3 years ago
6

I NEED HELP ON THIS

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

L'(-1,1)  M'(1,2)  N(1,-1)

Step-by-step explanation:

Now you just need to plot the 3 points and link them with lines and you will find the new triangle.

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Which is the function and how do you know?
il63 [147K]

Answer:

Option 4

Step-by-step explanation:

3 0
3 years ago
A 150-foot fence encloses a garden. What is the length of each side of the garden
Helga [31]
I Think 150 divided by 4=37.5
4 0
3 years ago
Read 2 more answers
Angles A and B are complementary angles in a right triange. The value of cos(A) is 12/13. What is the value of Tan(A)
Orlov [11]
Using the pythagorean identity, we can find the value of sin(A)

cos^2(A) + sin^2(A) = 1
(12/13)^2 + sin^2(A) = 1
144/169 + sin^2(A) = 1
sin^2(A) = 1 - 144/169
sin^2(A) = 169/169 - 144/169
sin^2(A) = (169 - 144)/169
sin^2(A) = 25/169
sin(A) = sqrt(25/169)
sin(A) = 5/13

Which is then used to find tan(A)

tan(A) = sin(A)/cos(A)
tan(A) = (5/13) divided by (12/13)
tan(A) = (5/13)*(13/12)
tan(A) = (5*13)/(13*12)
tan(A) = 5/12

The final answer is 5/12

5 0
3 years ago
According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a
Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, \mu = 2.58 and Standard deviation, \sigma = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

             Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar \leq 2.50)

P(Xbar < 2.66) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } } ) = P(Z < -1.68) = 1 - P(Z  1.68)

                                                              = 1 - 0.95352 = 0.04648

P(Xbar \leq 2.50) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }  ) = P(Z \leq  -3.92) = 1 - P(Z < 3.92)

                                                              = 1 - 0.99996 = 0.00004  

Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046

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3 years ago
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4 years ago
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