The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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Answer:
Step-by-step explanation:
Answer: 1/5 of the total distance to his grandmothers house was traveled on Sunday
The total distance to to his grandmothers house is assumed to be 1
Marks family traveled 7/10 of the distance to his grandmothers house on Saturday. The remaining distance would
1 - 7/10 = 3 /10
They traveled 2/3 of the remaining distance on Sunday. This means that the distance that they travelled on Sunday is
2/3 × 3/10 = 2/10 = 1/5
No because the exponent on 6^3 is 216 and if you use (4•6)^3 then you’ll have to multiply the quotations and then Square it to the third
Answer:
antonyms?
Step-by-step explanation:
The answer is 1,800, you would multiply 5 by 10 which is 50 then t would be 50 to the 4th power 50 times 4 is 200. then you do the same on the other side 3 time 10 which is 30 to the second power which is 90 than you multiply 200 and 90 because when you have two parentheses next to each other you always multiply but when you do that your answer turns out to be 1,800
