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9966 [12]
3 years ago
7

Please please help.

Mathematics
2 answers:
MariettaO [177]3 years ago
7 0

Answer:

1. x < -8

2. y + 2 > -5

3. Yes, because -16 is less than -3

4. No, because -6 is less than -4

5. a > 6

6. k < -11

7. y  > -6

8. b < -3/7

9. x > -2.8

10. r < -0.9

oee [108]3 years ago
4 0
Answer:5
Explanation: 5
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I need help pls i would really appreciate it !!
vlabodo [156]
Answer : a
Sin is opposite/hypotenuse which is 8/10
And this is 4/5
3 0
3 years ago
Read 2 more answers
5x-3-2x/7=24 solve for x
bearhunter [10]

Answer:

X=5.7

Step-by-step explanation:

5x-3-2x/7=24

We simplify the equation to the form, which is simple to understand  

5x-3-2x/7=24

Simplifying:

5x-3-0.285714285714x=24

We move all terms containing x to the left and all other terms to the right.  

+5x-0.285714285714x=+24+3

We simplify left and right side of the equation.  

+4.71428571429x=+27

We divide both sides of the equation by 4.71428571429 to get x.  

x=5.72727272727

7 0
3 years ago
What is the lateral area of a right cylinder if the radius of the base is 12 mm and the altitude of the cylinder is 5 times the
lakkis [162]
The lateral area of a cylinder is given by:
Area=πrl+2πr^2
radius,r=12 mm
length,l=5*12=60mm
therefore the lateral area will be:
Area=π*12*60
Area=2,261.95 mm^2
The area of the bases will be:
A=2*π*12^2=904.78 mm^s
The lateral area will be:
2,261.95+904.78
=3,166.73
=3167 mm^2
5 0
3 years ago
Simplify the expression:<br> 3j–1+4
RUDIKE [14]

Answer:

3j/3—5/3

J=5/3

hope helps

5 0
3 years ago
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
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