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2 years ago

Which equation can be used to solve for x?

Mathematics

2 answers:

Pani-rosa [81]2 years ago

5 0

Answer:

$\cos(x) = \frac{24}{30}$

OPTION C

kolbaska11 [484]2 years ago

3 0

The correct answer to your question is letter c

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Convert 213base four to base5

kakasveta [241]

Answer:

213 in base 4 = 124 in base 5

Step-by-step explanation:

First we convert base 4 to base 10

213 in base 4

2*42 + 1*41 + 3*40

32 + 4 + 3

39 in base 10

Now we convert base 10 to base 5

39/5

7/5 r = 4

1 r = 2

124 in base 5

Hence 213 in base 4 = 124 in base 5

4 0

3 years ago

Write the equation of the circle with center (0,0) and (3,6)

ruslelena [56]

Ya I cant help you :/

7 0

3 years ago

I need help ASAP please!!!

Aleksandr-060686 [28]

Answer: The answer is b 100+(-500)

Step-by-step explanation: If you solve for the original and this answer, they will both equal -400

8 0

3 years ago

Read 2 more answers

A total of four and x is less than or equal to 8

ANTONII [103]

4+x <u><</u> 8: i believe this would be the right answer

4 0

3 years ago

What is the monomial if a square of a monomial is:1 9/16 a12b6

san4es73 [151]

Answer:

$1\dfrac{1}{4}a^6b^3$

Step-by-step explanation:

A square of a monomial is $1\dfrac{9}{16}a^{12}b^6$ that is $\dfrac{25}{16}a^{12}b^{6}$

Use properties of exponents:

$(a^m)^n=a^{mn}\\ \\\dfrac{a^m}{b^m}=\left(\dfrac{a}{b}\right)^m\\ \\a^mb^m=(ab)^m$

Note that

$\dfrac{25}{16}=\dfrac{5^2}{4^2}=\left(\dfrac{5}{4}\right)^2\\ \\a^{12}=a^{6\cdot 2}=(a^6)^2\\ \\b^6=b^{3\cdot 2}=(b^3)^2$

Then

$\dfrac{25}{16}a^{12}b^{6}=\left(\dfrac{5}{4}\right)^2\cdot (a^6)^2\cdot (b^{3})^2=\left(\dfrac{5}{4}a^6b^3\right)^2$

So, the monomial is

$\dfrac{5}{4}a^6b^3=1\dfrac{1}{4}a^6b^3$

5 0

3 years ago