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Anna71 [15]
3 years ago
7

Indicate the method you would use to prove the two 's . If no method applies, enter "none".

Mathematics
1 answer:
netineya [11]3 years ago
5 0

Answer:

AAS

Step-by-step explanation:

It will be angle angle side because you are given a side and two angles, and when you put them in the correct order, you will get AAS, or SAA (not the correct way to say it)

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The first one is 0.97 the second one is 6
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7x-9x what is the answer
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-2x

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The expression itself is -2x. We subtract the coefficients 7 and 9 to get -2.

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In the diagram, the measures of angle 3 and angle 6 are 50 degrees. The measure of angle 5 is 130 degrees. Are lines c and d par
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9514 1404 393

Answer:

  (c)  Yes, because angle 3 and angle 6 are congruent

Step-by-step explanation:

Angles 3 and 6 are "alternate interior" angles. When those angles are congruent, as these are, then the lines crossed by the transversal are parallel.

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7 0
3 years ago
I NEED HELP !!! 30 points!!!! and brainliest :)<br><br>please give sensible answer :(<br><br><br>​
Allushta [10]

Answer:

Step-by-step explanation:

9) PQR Is an isosceles triangle

=> ∠PRQ = (180° - x)/2

PRS is an isosceles right triangle

=> ∠PRS = 45°

Have: ∠PRS + ∠PRQ = 115°

=> \frac{180-x}{2}+45=115 \\

=> 180 - x = (115 - 45).2 = 140

<=> x = 180 - 140 = 40

10) ABD is an isosceles right triangle => ∠ABD = 45°

BCD is an equilateral triangle => ∠CBD = 60°

have: x = ∠ABD + ∠CBD = 45° + 60° = 105°

11) have: x = y (2)

PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40

QTS   is an isosceles triangle => ∠TQS = 180 -2x

QRS   is an isosceles triangle => ∠RSQ = y

have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)

(1)(2) => \left \{ {{y=x} \atop {2x-y=40}} \right.\\\\=> \left \{ {{x=40} \atop {y=40}} \right.

=> x + y = 80

12) EFJ Is an equilateral  triangle => ∠FJE = 60

∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle

=> 60 = 2.∠JHF => ∠JHF = 30°

∠JHF is the outer angle of the triangle FHG

=> 30° = 2x

<=> x = 15°

7 0
3 years ago
Please help me solve this problem.
KatRina [158]
The square of the diagonal (d1) of the end face is
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The square of the longest diagonal (d2) will be given by
.. (d2)^2 = (3x in)^2 +(d1)^2
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So, the longest diagonal is
.. d2 = √(9x^2 +34) in
4 0
4 years ago
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