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barxatty [35]
2 years ago
13

What is the additive inverse of ?

Mathematics
1 answer:
AVprozaik [17]2 years ago
8 0
In mathematics, the additive inverse of a number a is the number that, when added to a yields zero. This operation is also known as the opposite (number), sign change, and negation. ... For example, the additive inverse of 7 is −7, because 7 + (−7) = 0, and the additive inverse of −0.3 is 0.3, because −0.3 + 0.3 = 0 .
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Which of the following values are in the range of the function graphed below? check all that apply
vodomira [7]

Answer:

Option D. 1

Option E. 1/2

Step-by-step explanation:

we know that

Looking at the graph

The domain is the interval ----> [-1,1]

-1\leq x\leq 1

The domain is all real numbers greater than or equal to -1 and less than or equal to 1

The range is the interval ----> [0,1]

0\leq y\leq 1

The range is all real numbers greater than or equal to 0 and less than or equal to 1

therefore

The values that are in the range are

1 and 1/2

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2 years ago
Read 2 more answers
Need help ASAP!!!!! I WILL GIVE THE MOST BRAINLIEST TO THE FIRST PERSON THAT ANSWERS
lys-0071 [83]

Answer:

x^2 + 10x + y^2 -4y + -7 = 0

Step-by-step explanation:

For any circle point with coordinate of center (a,b) and radius r

equation of circle is given by

(x-a)^2 + (y-b)^2 = r^2

_______________________________________

Given

coordinate of center =  (-5,2)

radius = 6

thus, equation of circle can be written by substituting a and b with (-5 ,2) and r =6 as shown below

(x-a)^2 + (y-b)^2 = r^2\\(x-(-5))^2 + (y-2)^2 = 6^2\\x^2 + 10x + 25 + y^2 -4y + 4 = 36\\=>x^2 + 10x + y^2 -4y + 29 = 36\\=>x^2 + 10x + y^2 -4y + 29 -36 = 36 -36\\=>x^2 + 10x + y^2 -4y + -7 = 0

Thus, equation of circle is x^2 + 10x + y^2 -4y + -7 = 0

3 0
3 years ago
Which undefined term is needed to define a circle?
Solnce55 [7]
A Point is needed to define a circle Hope this helps!!!
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3 years ago
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mixer [17]
Hello LovingAngel!

To find the slope, you can use the formulas \frac{rise}{run} as well as \frac{y^2-y^1}{x^2 - x^1}. I am using the latter to calculate and ensuring my answer with the former. 

[Note: (x,y) is the format for ordered pairs]

First pair:  value 1:(1,5) and value 2:(2,8) 
\frac{y^2-y^1}{x^2 - x^1} -> \frac{8 - 5}{2 - 1} -> \frac{3}{1} or 3. 

The slope for (1,5) and (2,8) is 3(/1). 

Second pair: value 1: (3,1) value 2 (3,-1)

\frac{y^2-y^1}{x^2 - x^1} -> \frac{-1 - 1}{3 - 3} -> \frac{-2}{0}
Slope for the second pair is -2/0

Checking work with \frac{rise}{run}
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1.  (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) <span>✔</span>

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Find the exact values of the remaining trigonometric functions of θ satisfying the given conditions. (if an answer is undefined,
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The answer is undefined.
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