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Svetllana [295]
3 years ago
12

Can one of y’all help me pls

Mathematics
1 answer:
Georgia [21]3 years ago
4 0

Answer:

<h2><u>Graph A. </u></h2>

Step-by-step explanation:

Since you are looking for a graph that shows a function, answer A has to be correct. If you look at graph B, C and D, none of these are functions

You can check if a graph shows a function using the vertical line test. Make a vertical line on any x value and if it passes through 2 or more lines, it is NOT a function

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Rochelle earned $500 during the summer. She put 35% of this amount into savings. Which of the following fraction is equivalent t
vivado [14]

Answer:

65/100 or 13/20

Step-by-step explanation:

65% = 65/100 and simplify to 13/20

6 0
3 years ago
Which of the following is the domain and range of the ellipse with equation x2 + 4y2 – 2x + 16y – 19 = 0?
Nata [24]

The option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7], and the range is R: [–5, 1]

<h3>What is an ellipse?</h3>

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have an ellipse equation:

\rm x^{2}+4y^{2}-2x+16y-19=0

We can write the above equation as:

\rm \dfrac{\left(x-1\right)^{2}}{36}+\dfrac{\left(y+2\right)^{2}}{9}=1

The domain will be:

D: [–5, 7]

The range will be:

R: [–5, 1]

Thus, the option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7] and the range is R: [–5, 1]

Learn more about the ellipse here:

brainly.com/question/19507943

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5 0
2 years ago
Figure G is rotated 90Degrees clockwise about the origin and then reflected over the x-axis, forming figure H.Which sequence of
Tasya [4]

Answer:

the answer is A

Step-by-step explanation:

hope it worked

3 0
3 years ago
Read 2 more answers
6.012<br> as a mixed number in simplest form.
Novosadov [1.4K]
6    3
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ignore this sentence
4 0
3 years ago
Read 2 more answers
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
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