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2 years ago

7

Solve for x. −3x + 2b > 8

1 answer:

damaskus [11]2 years ago

4 0

Answer:

x<2/3b+-8/3

Step-by-step explanation:

Let's solve for x.

−3x+2b>8

Step 1: Add -2b to both sides.

2b−3x+−2b>8+−2b

−3x>−2b+8

Step 2: Divide both sides by -3.

-3x/-3>-2b+8/-3

x<2/3b+-8/3

Answer is : x<2/3b+-8/3

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Part A: Solve A = (x + 23) for x. (4 points) Part B: Determine the value of x when A = 108. (2 points) Part C: Solve -np - 90 &g

Galina-37 [17]

<span>Part A: Solve A = (x + 23) for x.

A = x + 23

=> A - 23 = x + 23 - 23

=> A - 23 = x

=> x = A - 23 <------- answer

Part B: Determine the value of x when A = 108

Replace the value of A in the expression x = A - 23

x = 108 - 23 = 75

x = 75 <------- answer

Part C: Solve -np - 90 > 30 for n.

-np - 90 > 30

=> -np + np - 90 >30 + np

=> - 90 > 30 + np

=> -90 - 30 > 30 - 30 + np

=> -120 > np

=> np < - 120 <----- answer
</span>

7 0

3 years ago

zepelin [54]

Answer:

The required equation is: $\mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}$

Step-by-step explanation:

We need to find equation from the table given

x f(x)

3 -5

7 -2

11 1

15 4

We can write equation in the form of $y=mx+b$

where m is slope and b is y-intercept.

Finding Slope

We can used the slope formula to find slope: $Slope=\frac{y_2-y_1}{x_2-x_1}$

From the table we have: $x_1=3, y_1=-5, x_2=7, y_2=-2$

Putting values and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-(-5)}{7-3} \\Slope=\frac{-2+5}{7-3}\\Slope=\frac{3}{4}$

So, we get slope $m=\frac{3}{4}$

Now, finding y-intercept

Using the slope $m=\frac{3}{4}$ and point (3,-5) we can find y-intercept

$y=mx+b\\-5=\frac{3}{4}(3)+b\\-5=\frac{9}{4}+b\\b=-5-\frac{9}{4}\\b=\frac{-5*4-9}{4}\\b=\frac{-20-9}{4}\\b=\frac{-29}{4}$

The y-intercept is $b=\frac{-29}{4}$

So, the equation having slope $m=\frac{3}{4}$ and y-intercept $b=\frac{-29}{4}$ will be:

$y=mx+b\\y=\frac{3}{4}x-\frac{29}{4}$

The required equation is: $\mathbf{f(x)=\frac{3}{4}x-\frac{29}{4}}$

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