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2 years ago

Solve for x. −3x + 2b > 8

Mathematics

1 answer:

damaskus [11]2 years ago

4 0

Answer:

x<2/3b+-8/3

Step-by-step explanation:

Let's solve for x.

−3x+2b>8

Step 1: Add -2b to both sides.

2b−3x+−2b>8+−2b

−3x>−2b+8

Step 2: Divide both sides by -3.

-3x/-3>-2b+8/-3

x<2/3b+-8/3

Answer is : x<2/3b+-8/3

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An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

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1 year ago

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Arc AC would be 90 degrees because the line is bisects the straight line (180 Degrees)

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3 years ago

Tomas makes a balloon sculptures at a circus. In 180 minutes, he uses 253 balloons to make 36 identical balloon sculptures.

Kipish [7]

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