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andrew11 [14]
3 years ago
10

2. In a certain school, there are 7 teachers for every 252 students. If there are 468 students, how many

Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Answer:

66.6

Step-by-step explanation:

If 7 teachers for 252 student

We divide 468÷7= 66.6

66.6 teacher

Here you are

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Please answer I need an answer!!!
Sever21 [200]

Answer:

g=7.5

n=2.6

unless you want it in simplified fraction form

8 0
4 years ago
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b) In one year, Clara and Dave borrowed books from a library in the ratio 3:7. Dave borrowed 35 books. Work out the number of bo
tatiyna

3:7 =

3/7

3/7 = x/35

7x = 105

x = 15

answer : clara borrowed 15 books

7 0
2 years ago
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Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm
Andreyy89
Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
a(9) = a + 8d = 90
a(9) - a(4) => 5d = 35
d = 35/5 = 7.
From a(4): a = 55 - 3d = 55 - 3(7) = 55 - 21 = 34

a(2) = a + d = 34 + 7 = 41.

4 0
4 years ago
Please help, would be greatful :)
tankabanditka [31]

Answer:

x ≈ 25.5°

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle θ = <em>x</em>°

Opposite Leg = 10

Hypotenuse = 21

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [tangent]:                    tanx° = 10/21
  2. Inverse trig:                                  x° = tan⁻¹(10/21)
  3. Evaluate:                                      x = 25.4633°
  4. Round:                                          x ≈ 25.5°
8 0
3 years ago
What unbalanced force is required to accelerate a 1500 kg race car at 3.00 m/s/s?
AfilCa [17]
Answer:166.66

Step by step explanation
4 0
3 years ago
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