Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula, 
= a + (n-1)d
here, is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
Answer:
1/36
Step-by-step explanation:
If a cube rolls and it landed on one it’s 1/6 if u rolled he same cube and got one too then it’s still 1/6 so now u just multiply them
Hope this helps
Answer:
11. This is counting only odd numbers, or counting by two starting with one.
Y<span>≥18
You want to get the y only on one side of the equation. To get rid of the -6 you have to add 6 to both sides to even out the equation.
y-6</span><span>≥</span><span>12
+6 +6
y </span>≥18
(3x-4y)^2=9x^2-24x+16y^2
(3x-2)(9x^2+6x+4)=27x^3-8
