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Mathematics

2 answers:

gulaghasi [49]3 years ago

8 0

Answer:

A. x^7

Step-by-step explanation:

Whenever you are dividing the same term with different exponents, you will subtract the exponents.

For this problem, we are going to subtract 4 from 11:

11 - 4 = 7

There you have it! you will get x^7.

And, if you really did write 11 x's and divided it by 4 x's, the 4 x's would cancel out, leaving you with 7 still remaining :D

Hope I helped!

-Mary

castortr0y [4]3 years ago

6 0

Answer:

$x^{7}$

Step-by-step explanation:

because $x^{11}/x^{4} \\$ is 11-4, which is 7. And you don't change the x.

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(3-4i)(6i+7)-(2-3i)

Sergeu [11.5K]

Answer:

43-7i

Step-by-step explanation:

We are given the expression:

$\displaystyle \large{(3 - 4i)(6i + 7) - (2 - 3i)}$

First, expand 3-4i in 6i+7. To expand binomial with binomial, first we expand 3 in 6i+7 then expand -4i in 6i+7.

$\displaystyle \large{[(3 \cdot 6i) + (3 \cdot 7) + ( - 4i \cdot 6i) + ( - 4i \cdot 7)]- (2 - 3i)} \\ \displaystyle \large{[18i + 21 - 24 {i}^{2} - 28i]- (2 - 3i)}$

Now combine like terms.

$\displaystyle \large{[ - 10i+ 21 - 24 {i}^{2} ]- (2 - 3i)}$

Imaginary Unit

$\displaystyle \large{i = \sqrt{ - 1} } \\ \displaystyle \large{ {i}^{2} = - 1 }$

Therefore:-

$\displaystyle \large{[ - 10i+ 21 - 24 ( - 1) ]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 21 + 24]- (2 - 3i)} \\ \displaystyle \large{[ - 10i+ 45]- (2 - 3i)}$