4x²-5=3x+4
4x²-3x-9=0
x=(3±√((-3)²-4*4*-9))/2*4
x=3±√(9+144) /8
x=(3±√153) /8
x=⅜±√153/8
Assuming the price of the pool does not change, then
Additional interest required is 4500-3750=750
using
I=Pit, we set up equation
750=3750*0.055*t
Solve for t
t=750/(3750*0.055)=3.64 years.
So will need to wait 3.64 years, or rounded up to 4 years.
5 is the y intercept.
-Always the number without the variable.
The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Given an equation showing profits of A Christmas vendor as
P=-0.1
+30g-1200.
We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.
To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.
665.60=-0.1
+30g-1200
0.1
-30g+1200+665.60=0
0.1
-30g+1865.60=0
Divide the above equation by 0.1.
-300g+18656=0
Solving for g we get,
g=[300±
]/2*1
g=[300±![\sqrt{90000-74624}]/2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-74624%7D%5D%2F2)
g=[300±
]/2
g=(300±124)/2
g=(300+124)/2 , g=(300-124)/2
g=424/2, g=176/2
g=212,88
Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.
Put the value of P=1500 in equation P=-0.1
+30g-1200.
-0.1
+30g-1200=1500
0.1
-30g+1500+1200=0
0.1
-30g+2700=0
Dividing equation by 0.1.
-300g+27000=0
Solving the equation for finding value of g.
g=[300±
]/2*1
=[300±![\sqrt{90000-108000}] /2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-108000%7D%5D%20%2F2)
=[300±
]/2
Because
comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.
Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
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Answer:

Step-by-step explanation:
There is no graph posted, but y-intercepts are <em>x</em>'s are set equal to zero.
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