Answer D). 9 ft is correct
Height of the ball at a horizontal distance of 10 feet is 9 ft
Step-by-step explanation:
A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).
Y(x) = 
Question asked is " What will be height (Y) of the ball when X=10 ft "
Simply putting value of X in given equation
we get,
Y(x) =
Y(x) = 
Y(x) = 
Y(x) = 
Y(x) = 
<em>Therefore,</em> Height of the ball at a horizontal distance of 10 feet is 9 ft
Answer D. 9 ft is correct
240 = 2 × 120
120 = 2 × 60
60 = 2 × 30
30 = 2 × 15
15 = 3 × 5
The 2, 2, 2, 2, 3 and 5 are all the prime factors of 240. So, 2^4 × 3 × 5
1500 = 3 × 500
500 = 5 × 100
100 = 5 × 20
20= 5 × 4
4 = 2 × 2
The 3, 5, 5, 5, 2 and 2 are all the prime factors of 1500. So, 2² + 3 + 5³
Answer:
If the statement is true, lines a and b are parallel
Step-by-step explanation:
This is due to lines intersecting with line m at identical angles.
Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.
Given:
Ray QS bisects ∠PQR.
m∠PQS = 3x
m∠SQR = 5x-20
To find:
The value of x and m∠PQR
Solution:
Ray QS bisects ∠PQR. So,
The value of x is 10.
Now,
Put x=10,
Therefore, the m∠PQR is 60 degrees.
