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Scilla [17]
3 years ago
13

Marcus collects donations and sends care packages to troops overseas. He has 36 bars of soap and 24 toothbrushes and wants to ar

range the items so the packages are identical. What is the greatest number of packages that Marcus can make using all the soap and toothbrushes? ) What is the greatest number of packages of soap and toothbrushes that Marcus can make? Marcus can make at most 12 packages. ) How many bars of soap and toothbrushes are in each package? 2 toothbrushes in each pockage 6) There are ? bars of soap and ? toothbrushes in each package?​
Mathematics
2 answers:
xenn [34]3 years ago
7 0

Answer:

Marcus can make 12 packages, with 2 toothbrushes and 3 bars of soap in each package.

Step-by-step explanation:

For all the packages to be identical, they must all contain the same numbers of soaps and the same nuber of toothbrushes.

The ratior of soaps to brushes is 36/24 = 3/2

He could make 24 packages, each with 1 tootbrush and (3/2) bars of soap.

Assuming he is not going to cut soap bars in half, that is no good.

To make the numbers of individual items come out as integers, the smallest number he can multiply them by is the denominator on the (3/2) bar of soap. That would be a 2.

So he can makes packages with toothbrushes =    2 x 1 =2

                                                and soap bars    = 3/2 x 2 = 3

He can put 5 items in each package - 3 soap bars and 2 toothbrushes.

That means he makes 12 packages.

Flauer [41]3 years ago
5 0

Answer:

12, second one is 2 and 3.

Step-by-step explanation:

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The average life of a bread-making machine is 7 years, with a standard deviation of 1 year. Assuming that the lives of these mac
Alina [70]

Answer:

a) P(6.4

b) a=7 +1.036*0.333=7.345

So the value of bread-making machine that separates the bottom 85% of data from the top 15% is 7.345.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable life of a bread making machine. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =7,\sigma =1)

We take a sample of n=9 . That represent the sample size.

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=7, \frac{1}{\sqrt{9}})

Solution to the problem

Part a

(a) the probability that the mean life of a random sample  of 9 such machines falls between 6.4 and 7.2

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{1}{\sqrt{9}}=0.333

We want this probability:

P(6.4

Part b

b) The value of x to the right of which 15% of the  means computed from random samples of size 9 would fall.

For this part we want to find a value a, such that we satisfy this condition:

P(\bar X>a)=0.15   (a)

P(\bar X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.036. On this case P(Z<1.036)=0.85 and P(Z>1.036)=0.15

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.036

And if we solve for a we got

a=7 +1.036*0.333=7.345

So the value of bread-making machine that separates the bottom 85% of data from the top 15% is 7.345.

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