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tigry1 [53]
3 years ago
11

If cos A = 0.8945, find the measure of angle A to the nearest degree.

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0
I'm sorry but I don't know but can you help me?
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If you are good at math please help me answer all 4 please
Strike441 [17]
Slope = rise/run
1. Slope is -1/3
2. Slope is 3
3. Slope is -3/2
4. Slope is 3/2
5 0
3 years ago
Need help please thank you
umka21 [38]
2 cakes - Theresa's and Joe's
Theresa's cake had 6 pieces after she cut it. (2 times the size of Joe's pieces)
Joe's cake had 12 pieces after he cut it. (1/2 the size of Theresa's pieces)

We know that 8/12ths of ONE cake were eaten and that Joe ate 2 of his pieces.
We want to know how many pieces Theresa ate of her cake. Keeping in mind that her pieces are equal to 2 of Joe's pieces we can solve this question. 

8/12 eaten total
if 2/12 by Joe
then 8-2 = 6, 6/12 by Theresa
(BUT: Theresa's pieces were twice the size of Joe's so we will divide by 2)
6/12 = 3/6

Answer: Theresa ate 3 pieces of her cake

7 0
3 years ago
Find the value of x and y
NISA [10]
The answer is C. For sure
3 0
3 years ago
Math be hard- Can ya help?
horrorfan [7]

Answer:

1/8

Step-by-step explanation:

The slope equation for this problem is

y2-y1

--------

x2-x1

So the y2=4, y1=3, x2=8, and x1=0

4-3      =1

-----       --

8-0     =8

Which is 1/8

7 0
3 years ago
Read 2 more answers
An airplane is traveling at a speed of 240 miles/hour with a bearing of 110°. The wind velocity is 56 miles/hour at a bearing of
vodka [1.7K]

Answer:

Actual speed = 288 miles per hour

Actual direction angle = 116.38^\circ

Step-by-step explanation:

"Bearing" is the relative position of an object outside the plane compared to the position of the plane.  

Heading the the direction the nose of the plane is pointing.  

Course is the direction that pilot wants the plane to go.  

Wind direction is always the direction the wind is blowing from.  

The airplane is traveling at a speed of 240 miles/hour with a bearing of 110°.  

If the plane is traveling with a bearing of 110° and the wind is blown at a bearing of 325°.  

 325^{\circ}- 110^{\circ} =225^{\circ}

215^{\circ}- 180^{\circ} =35^{\circ}

The Ground speed will be in excess of the airspeed and true direction will be south if the indicated heading.  

The tailwind component is:

56 cos (35^\circ)

And the cross wind component is:

56 sin (35^\circ)  


And that is,

C^2 = (286)^2 + (32)^2


c = 288

So the actual speed of the plane is 288 miles per hour.

The deviation in the direction is:

Let the direction angle be 'x'.

x = tan ^{-1}\left ( \frac{32}{286} \right )=6.38^\circ

So the actual direction angle is 110^\circ+ 6.38^\circ=116.38^\circ.

5 0
3 years ago
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