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Wewaii [24]
3 years ago
14

Find the equation of the line that is perpendicular to the given line and passes through the given point.

Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

<em>y = 2x - 26 </em>

Step-by-step explanation:

y = -\frac{1}{2} x - 9 ⇒ slope m = -\frac{1}{2} ⇒ slope of ⊥ line m = 2

(13, 0)

y - 0 = 2(x - 13)

<em>y = 2x - 26</em>

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The measures of the angles of △ABC are given by the expressions in the table. Angle Measure A ​ (4x−13)° ​ B 15° C (x+18)∘ What
mr_godi [17]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles given and equate to 180

4x - 13 + 15 + x + 18 = 180 ( simplify left side )

5x + 20 = 180 ( subtract 20 from both sides )

5x = 160 ( divide both sides by 5 )

x = 32

∠A = 4x - 13 = (4 × 32) - 13 = 128 - 13 = 115°

∠C = x + 18 = 32 + 18 = 50°

As a check : 115° + 15° + 50° = 180° ← correct


7 0
3 years ago
Read 2 more answers
For a real number a, a+ 0 = a
mel-nik [20]


I think it's true.
Because any number added to 0 is equal to itself.
5 0
3 years ago
There are 4 tables. Students sit at each table evenly. There is two teachers assigned to the class. There are 21 students assign
klio [65]
The equation is 4s=21

You then divide 21 by 4. Because this ends in a decimal the answer cannot be found
7 0
3 years ago
Is the equations of quadratic number pattern will always have real roots
algol [13]
No, not at all.

The general quadratic equation is

                         Ax² + Bx + C = 0 .

The roots are real only if  (B² - 4AC) is not negative.

That means if you graph it, it touches or crosses the x-axis.

If the graph is up in the air and never touches the x-axis,
then it has no real roots.
8 0
3 years ago
-8x2(x+8)=8(2+6) how do i solve this and 4n+3/2=2n-5/1?
Marat540 [252]

1) -8x^2\left(x+8\right)=8\left(2+6\right)

-8x^3-64x^2=64

-8x^3-64x^2-64=64-64

-8x^3-64x^2-64=0

-8x^2+0.97035\dots x-7.88051\dots \approx \:0

x\approx \:-8.12129\dots

2) 4n+\frac{3}{2}=2n-\frac{5}{1}

4n+\frac{3}{2}=2n-5

4n+\frac{3}{2}-\frac{3}{2}=2n-5-\frac{3}{2}

4n=2n-\frac{13}{2}

4n-2n=2n-\frac{13}{2}-2n

2n=-\frac{13}{2}

\frac{2n}{2}=\frac{-\frac{13}{2}}{2}

n=-\frac{13}{4}

6 0
3 years ago
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