Question

A line passes through the point (-4,7) and has a slope of 3/2

Answer 1

Answer:

$y=\frac{3}{2}x + 13$

Step-by-step explanation:

Given that $x_{1}$ = -4 and $y_{1}$ = 7 (from the point given) and m = $\frac{3}{2}$, we will use the equation $y - y_{1} =m(x-x_{1})$. Therefore, when we substitute the given values to the equation:

y - y1 = m(x - x1)

y - 7 = 3/2(x - (-4))

y - 7 = 3/2(x + 4)

y - 7 = 3/2x + 6

y = 3/2x + 6 + 7

y = 3/2x + 13

Answer 2

Answer:

y = $\frac{3}{2}$ x + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{3}{2}$ , then

y = $\frac{3}{2}$ x + c ← is the partial equation

To find c substitute (- 4, 7) into the partial equation

7 = - 6 + c ⇒ c = 7 + 6 = 13

y = $\frac{3}{2}$ x + 13 ← equation of line