Answer:
Step-by-step explanation:
Given the sample data
Pre-test... 12 14 11 12 13
Post-Test 15 17 11 13 12
The mean of pre-test
x = ΣX / n
x = (12+14+11+12+13) / 5
x = 12.4
The standard deviation of pre-test
S.D = √Σ(X-x)² / n
S.D = √[(12-12.4)²+(14-12.4)²+(11-12.4)²+(12-12.4)²+(13-12.4)² / 5]
S.D = √(5.2 / 5)
S.D = 1.02.
The mean of post-test
x' = ΣX / n
x' = (15+17+11+13+12) / 5
x' = 13.6
The standard deviation of post-test
S.D' = √Σ(X-x)² / n
S.D' = √[(15-13.6)²+(17-13.6)²+(11-13.6)²+(13-13.6)²+(12-13.6)² / 5]
S.D = √(23.2 / 5)
S.D = 2.15
Test value
t = (sample difference − hypothesized difference) / standard error of the difference
t = [(x-x') - (μ- μ')] / (S.D / n — S.D'/n)
t = (12.4-13.6) - (μ-μ')/ (1.02/5 - 2.15/5)
-1.5 = -1.2 - (μ-μ') / -0.226
-1.5 × -0.226 = -1.2 -(μ-μ')
0.339 = -1.2 - (μ-μ')
(μ-μ') = -1.2 -0.339
μ-μ' = -1.539
Then, μ ≠ μ'
We can calculate our P-value using table.
This is a two-sided test, so the P-value is the combined area in both scores.
The p-value is 0.172
The p value > 0.1
Answer:
A. If the dividend is greater than the divisor, the quotient will be greater than 1.
Step-by-step explanation:
Checking all options
A. If the dividend is greater than the divisor, the quotient will be greater than 1.
That is,
4 ÷ 3 = 1.33
Where,
4 is the dividend
3 is the divisor
1.33 is the quotient
THIS IS TRUE
B.If the dividend is less than the divisor, the quotient will be greater than 1
That is,
3 ÷ 4 = 0.75
Where,
3 is the dividend
4 is the divisor
0.75 is the quotient
NOT TRUE
C. If the dividend is equal to the divisor, the quotient will be less than 1
That is,
3 ÷ 3 = 1
Where,
3 is the dividend
3 is the divisor
1 is the quotient
NOT TRUE
D. If the dividend is greater than the divisor, the quotient will be less than 1.
That is,
4 ÷ 3 = 1.33
Where,
4 is the dividend
3 is the divisor
1.33 is the quotient
NOT TRUE
Therefore, option A is TRUE
Answer:
The answer is D.
Step-by-step explanation:
It is D because they cannot be negative feet away and if the fisherman is 12ft above water and the diver is 40ft below than 40 + 12 = 52. Hope this helps.
Answer:
Option B. m⁷/n² is the correct answer.
Step-by-step explanation:
Identity,
xᵃ * xᵇ = xᵃ⁺ᵇ
xᵃ/xᵇ = xᵃ⁻ᵇ
x⁻ᵃ = 1/xᵃ
It is given that,
m⁻⁶ n⁻³/m⁻¹³ n⁻¹
Using these three identities we can write,
m⁻⁶ n⁻³/m⁻¹³ n⁻¹ = m⁻⁶ m¹³/n⁻¹n³ (since x⁻ᵃ = 1/xᵃ)
m⁻⁶ m¹³/n⁻¹n³ =m⁽⁻⁶⁺¹³⁾/n⁽⁻¹⁺³⁾ = m⁷/n² (since xᵃ * xᵇ = xᵃ⁺ᵇ and xᵃ/xᵇ = xᵃ⁻ᵇ)
Therefore Option B. m⁷/n² is the correct answer
Answer:
Step-by-step explanation:
The input it taken as the unknown base value, while the output here is the area of the trapezoid. b is therefore the base value, and A( b ) is the area of the trapezoid. Let's formulate the equation for the area of the trapezoid, and isolate the area of the trapezoid. To find the inverse of this function, switch y ( this is A( b ) ) and b, solving for y once more, y ➡ y ⁻ ¹.
y = height 
( ( unknown base value ( b ) + 7 ) / 2 ),
y = 10 ( ( b + 7 ) / 2 )
Now switch the positions of y and b -
b = 10 ( ( y + 7 ) / 2 ) or 
- now that we are going to take the inverse ( y ⁻ ¹ ) or B( a ), b will now be changed to a,
,
Therefore the equation that represents the inverse function will be the following : B(a) = a / 5 - 7
