Let the numbers be x and y
x + y = 57 ........(i)
x - y = 13 ........(ii)
Add equations (i) and (ii) to eliminate y
x + y + x - y = 57 + 13
x + x + y - y = 57 +13
2x = 70
x = 70/2 = 35
From (i) x + y = 57
35 + y = 57
y = 57 - 35
y = 22
The numbers are 35 and 22.
Answer:
53 + 1 = 54
give me brainllest if this is right okay?
Answer:
He did NOT apply the distributive property correctly for 8(1 + 2i)
Answer:
−0.989010989010
Step-by-step explanation:
what is the 45th term of a sequence generated by the formula tn=(-1)^n * (2n/2n+1)?
When n= 45
tn=(-1)^n*(2n/2n+1)
tn = (-1)^45 * ( 2(45) / 2(45) + 1
= -1 * 90 / (90+1)
= -90 / 91
= −0.989010989010
The 45th term of the sequence generated by the formula tn=(-1)^n*(2n/2n+1) is −0.989010989010
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
