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3 years ago

PLEASE SOLVE THESE QUESTIONS WITH EXPLANATION

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

Answer:

1) 194

2) 480

3) 144

4) 2m > 84 $

4m > 168 $

10m> 420 $

13m> 546$

Step-by-step explanation:

1) 582 in 30 mins ... so in third the time 582÷3 = 194

2)120 tools in 5 hours , so 120 ÷ 5 = 24 tools per hour > so 24 × 20 = 480

3) 1kg is for 18$ ... so 8kg will be 8 × 18 = 144

4) 5meters cost 210$ , one meter costs 210÷5 =42

now multiply , 2×42 = 84 , 4×42 = 168 , 10×42= 420 , 13×42 = 546

sorry the last question isn't showing for me , i can't see it

STatiana [176]3 years ago

7 0

I agree with the person ^^^

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Write a number sentence to add 6 ones to 21.Write number sentence to add 6 tens to 21

Semenov [28]

I do suppose that you refer to adding these quantities:
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and
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4 years ago

Can I get some help please? Show your work Thanks!

grigory [225]

Hey Gary :) Nice to see you around

For this question, we want to use logarithmic rules to write the expression as a single logarithm.
Using the rule $log_{b} ( M^{k} ) = k * log_{b} M$ , we can simplify
$3log_{b} q$ to $log_{b} ( q^{3} )$ . We can also simplify $6log_{b}(v)$ to $log_{b}( v^{6})$ .

So, we have $log_{b} ( q^{3} )$ + $log_{b}( v^{6})$ .

Another logarithmic rule is:
$log_{b}(M*N) = log_{b} M + log_{b} N
$

Using this rule, we can use the logs we have calculated and change them to:
$log_{b}( q^{3} v^{6})$

This matches answer choice A.

Hope this helps! Feel free to contact me with any questions.

4 0

3 years ago

A search committee is formed to find a new software engineer.

Free_Kalibri [48]

Answer:

(a) 1,902,231,808,400

(b) 84

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!\cdot(n-k)!}$

(a)

Compute the number of ways to select 9 applicants from 100 as follows:

${100\choose 9}=\frac{100!}{9!\cdot(100-9)!}$

$=\frac{100!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92\times 91!}{9!\times 91!}\\\\=\frac{100\times 99\times 98\times 97\times 96\times 95\times 94\times 93\times 92}{9!}\\\\=1902231808400$