ANSWER ASAP GIVING BRAINLIEST AND FIVE STARS!

Mathematics

1 answer:

algol133 years ago

7 0

Answer:

Step-by-step explanation:

It is not necessary to have a common denominator when multiplying fractions. To multiply fractions with different denominators, you multiply the numerators with each other and then the denominators with each other. The end product of multiplying fractions with no common denominator may not be in its lowest terms however, and might need to be reduced. For example, if you were to multiply 1/2 by 2/3, you would first multiply the numerators (1 and 2) to get 2, and then the denominators (2 and 3) for a product of 2/6. After getting this product, reduce it to its lowest terms, end up with 1/2 by dividing both the numerator and denominator by 2, and end up with 1/3 as a final product. Thus, it is not necessary to have common denominators when multiplying fractions.

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Two numbers multiply to be -7 and add to be -6. What are the numbers?<br><br> Example; 2,3

rewona [7]

<u>Given</u>:

Let the two numbers be x and y.

Two numbers multiply to be -7 and add to be -6.

This can be written in equation as,

$xy=-7$ and

$x+y=-6$

<u>Value of the two numbers:</u>

Let us determine the value of the two numbers using substitution method.

Substituting $y=-6-x$ in the equation $xy=-7$ , we get;

$x(-6-x)=-7$

Simplifying, we get;

$-6x-x^2=-7$

$x^2+6x-7=0$

$(x+7)(x-1)=0$

$x=-7, 1$

Thus, the values of x are x = 1,-7

When x = 1 , the equation $x+y=-6$ becomes $y=-7$

When x = -7, the equation $x+y=-6$ becomes $y=1$

Therefore, the two numbers are 1 and -7

3 0

3 years ago

Out of 100 people sampled, 42 had kids. Based on this, construct a 99% confidence interval for the true population proportion of

maksim [4K]

Answer:

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.